15y^{''}+26y^'+7y=0,y(0)=8,y^'(0)=1

Lösung

15 y^{^{''}} + 26 y^{^{'}} + 7 y = 0, y (0) = 8, y^{^{'}} (0) = 1

y = (8 + \frac{55}{16}) e^{- \frac{t}{3}} - \frac{55}{16} e^{- \frac{7 t}{5}}

Schritte zur Lösung

15 y^{''} (t) + 26 y^{'} (t) + 7 y = 0

Solve linear ODE:

y = (8 + \frac{55}{16}) e^{- \frac{t}{3}} - \frac{55}{16} e^{- \frac{7 t}{5}}

y = (8 + \frac{55}{16}) e^{- \frac{t}{3}} - \frac{55}{16} e^{- \frac{7 t}{5}}

10 y^{^{''''}} + 13 y^{^{''}} + 4 y = 0

l in e a r y^{^{''}} - 4 y^{^{'}} + 5 y = 0, y (0) = 2, y^{^{'}} (0) = 1

y^{^{''}} + 4 y^{^{'}} + 4 y = 0, y (- 1) = 4, y^{^{'}} (- 1) = 6

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y^{1} (0) = e^{3} x

5 \frac{d ^{2} y}{d x ^{2}} + \frac{d y}{d x} = 0