2u^{''}+u^'+3\H(t)=0

Lösung

2 u^{''} + u^{'} + 3 H (t (x)) = 0

2 \cdot 0 + 0 + 3 H (t (x)) = 0

Schritte zur Lösung

2 u^{''} + u^{'} + 3 H (t (x)) = 0

u^{''} = 0

2 \cdot 0 + u^{^{'}} + 3 H (t (x)) = 0

u^{'} = 0

2 \cdot 0 + 0 + 3 H (t (x)) = 0

y^{^{''}} + 2 y^{^{'}} - 10 y = 0, y (0) = 2, y^{^{'}} (0) = - 1

2 y^{^{''}} - 0 y^{^{'}} + 18 y = 0

24 y^{^{''}} + 14 y^{^{'}} - 3 y = 0

y^{^{''}} + 5 \cdot y^{^{'}} + a \cdot y = 0, y (0) = 1, y^{^{'}} (0) = 7

5 y^{^{''}} + c y^{^{'}} + 45 y = 0, y (0) = - 8, y^{^{'}} (0) = 0