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Beliebt Rechnen >

y^{''}+8y^'+25y=0,y(0)=2,y(0)=-7

Lösung

y^{^{''}} + 8 y^{^{'}} + 25 y = 0, y (0) = 2, y (0) = - 7

Lösung

y = e^{- 4 t} (2 cos (3 t) + c_{2} sin (3 t))

Schritte zur Lösung

y^{''} (t) + 8 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = e^{- 4 t} (2 cos (3 t) + c_{2} sin (3 t))

y = e^{- 4 t} (2 cos (3 t) + c_{2} sin (3 t))

Graph

Beliebte Beispiele

2(d^2y)/(dx^2)-(dy)/(dx)-6y=0

2 \frac{d ^{2} y}{d x ^{2}} - \frac{d y}{d x} - 6 y = 0

y^{^{'''}} = - y

(d^2y)/(dx^2)-8(dy)/(dx)=0

\frac{d ^{2} y}{d x ^{2}} - 8 \frac{d y}{d x} = 0

y^{''}+8y^'+25y=0,y^'(0)=2

y^{^{''}} + 8 y^{^{'}} + 25 y = 0, y^{^{'}} (0) = 2

y^{'''}+3y^{''}-18y^'-40y=0

y^{^{'''}} + 3 y^{^{''}} - 18 y^{^{'}} - 40 y = 0