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Beliebt Rechnen >

4y^{''}+y^'-2y=0

Lösung

4 y^{^{''}} + y^{^{'}} - 2 y = 0

Lösung

y = c_{1} e^{\frac{( - 1 + 33 ) t}{8}} + c_{2} e^{\frac{( - 1 - 33 ) t}{8}}

Schritte zur Lösung

4 y^{''} (t) + y^{'} (t) - 2 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( - 1 + 33 ) t}{8}} + c_{2} e^{\frac{( - 1 - 33 ) t}{8}}

y = c_{1} e^{\frac{( - 1 + 33 ) t}{8}} + c_{2} e^{\frac{( - 1 - 33 ) t}{8}}

Graph

Beliebte Beispiele

(d^2y)/(dt^2)+k^2y=0

\frac{d ^{2} y}{d t ^{2}} + k^{2} y = 0

10y^{''}+12y^'-18y=0

10 y^{^{''}} + 12 y^{^{'}} - 18 y = 0

y^{'''}+19y^{''}+97y^'+79y=0

y^{^{'''}} + 19 y^{^{''}} + 97 y^{^{'}} + 79 y = 0

y^{''}+3y^'-16y=0

y^{^{''}} + 3 y^{^{'}} - 16 y = 0

4y^{''}+4y^'+17y=0,y(0)=2

4 y^{^{''}} + 4 y^{^{'}} + 17 y = 0, y (0) = 2