16*y^{'''}-y^'=0

Lösung

16 \cdot y^{^{'''}} - y^{^{'}} = 0

y = c_{1} + c_{2} e^{- \frac{t}{4}} + c_{3} e^{\frac{t}{4}}

Schritte zur Lösung

16 \cdot y^{'''} (t) - y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{t}{4}} + c_{3} e^{\frac{t}{4}}

y = c_{1} + c_{2} e^{- \frac{t}{4}} + c_{3} e^{\frac{t}{4}}

y^{^{''}} - 6 y^{^{'}} + 10 y = 0, y (0) = - 1, y^{^{'}} (0) = 3

20 y^{^{''}} - 100 y^{^{'}} + 133 y = 0

y^{^{'''}} + 9 y^{^{'}} = 0, y^{^{''}} (0) = 27

x^{^{''}} + 6 x^{^{'}} + 8 x = 0, x (0) = 1, x^{^{'}} (0) = 2

y^{^{''}} - 10 y^{^{'}} + 9 y = 0, y (0) = - 1, y^{^{'}} (0) = 2