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Beliebt Rechnen >

16y^{''}-32y^'+65y=0

Lösung

16 y^{^{''}} - 32 y^{^{'}} + 65 y = 0

Lösung

y = e^{t} (c_{1} cos (\frac{7 t}{4}) + c_{2} sin (\frac{7 t}{4}))

Schritte zur Lösung

16 y^{''} (t) - 32 y^{'} (t) + 65 y = 0

Solve linear ODE:

y = e^{t} (c_{1} cos (\frac{7 t}{4}) + c_{2} sin (\frac{7 t}{4}))

y = e^{t} (c_{1} cos (\frac{7 t}{4}) + c_{2} sin (\frac{7 t}{4}))

Graph

Beliebte Beispiele

4y^{''}+5y^'-6y=0

4 y^{^{''}} + 5 y^{^{'}} - 6 y = 0

1/8 y^{''}+4y^'+16y=0,y(0)=0,y^'(0)=9

\frac{1}{8} y^{^{''}} + 4 y^{^{'}} + 16 y = 0, y (0) = 0, y^{^{'}} (0) = 9

2y^{'''}-y^{''}-y=0

2 y^{^{'''}} - y^{^{''}} - y = 0

y^{''}-y=0,y(0)=e^x

y^{^{''}} - y = 0, y (0) = e^{x}

y^{''}-10y^'+25y=0,y(0)=e^{5x}

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = e^{5 x}