6y^{''}-y^'-y=0,y(0)=1.25

Lösung

6 y^{^{''}} - y^{^{'}} - y = 0, y (0) = 1.25

y = (1.25 - c_{2}) e^{\frac{t}{2}} + c_{2} e^{- \frac{t}{3}}

Schritte zur Lösung

6 y^{''} (t) - y^{'} (t) - y = 0

Solve linear ODE:

y = (1.25 - c_{2}) e^{\frac{t}{2}} + c_{2} e^{- \frac{t}{3}}

y = (1.25 - c_{2}) e^{\frac{t}{2}} + c_{2} e^{- \frac{t}{3}}

y^{^{''}} - 11 y + 24 y = 0

y^{^{''}} + 3 y^{^{'}} - 10 y = 0, y (0) = α, y^{^{'}} (0) = 1

4 y^{^{''}} + 8 y^{^{'}} - 21 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + 3 y^{^{'}} - 10 y = 0, y (0) = α, y^{^{'}} (0) = 5

l in e a r y^{^{''}} + 49 y = 0