y^{''}+10y^'+9y=0

Lösung

y^{^{''}} + 10 y^{^{'}} + 9 y = 0

y = c_{1} e^{- t} + c_{2} e^{- 9 t}

Schritte zur Lösung

y^{''} (t) + 10 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{- 9 t}

y = c_{1} e^{- t} + c_{2} e^{- 9 t}

y^{^{''}} - 11 y^{^{'}} - 28 y = 0

y^{^{'''}} - 7 y^{^{''}} + 11 y^{^{'}} - 5 y = 0

f^{^{''}} (t) = f (t)

y^{^{''}} - 4 y^{^{'}} + 5 y = 1 + t, y (0) = 0, y^{^{'}} (0) = 4

y^{^{''}} - 2 y + 3 = 0