laplacetransform e^{-t}sin(3t)

Lösung

laplace transformation

e^{- t} sin (3 t)

\frac{3}{( s + 1 ) ^{2} + 9}

Schritte zur Lösung

L {e^{- t} sin (3 t)}

Wende Transformationsregel an: wenn

L {f (t)} = F (s)

dann

L {e^{a t} f (t)} = F (s - a)

Für

e^{- t} sin (3 t) : f (t) = sin (3 t), a = - 1

= L {sin (3 t)} (s + 1)

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= \frac{3}{( s + 1 ) ^{2} + 9}

\frac{d}{d x} (cos (x - x^{2}) (1 - 2 x))

x \to 0 lim (\frac{1}{x} ln (1 - 2 x))

\frac{d}{d x} (\frac{2 x + 3 x ^{2}}{x ^{2} e ^{x}})

l a pl a ce t r an s f or m t e^{- 3 t} cos (3 t)

\frac{d}{d x} (\frac{80 - x}{4})