derivative of sqrt(2x^2+2)

Lösung

\frac{d}{d x} (2 x^{2} + 2)

\frac{2 x}{2 x ^{2} + 2}

Schritte zur Lösung

\frac{d}{d x} (2 x^{2} + 2)

Wende die Kettenregel an:

\frac{1}{2 2 x ^{2} + 2} \frac{d}{d x} (2 x^{2} + 2)

= \frac{1}{2 2 x ^{2} + 2} \frac{d}{d x} (2 x^{2} + 2)

\frac{d}{d x} (2 x^{2} + 2) = 4 x

= \frac{1}{2 2 x ^{2} + 2} \cdot 4 x

Vereinfache

\frac{1}{2 2 x ^{2} + 2} \cdot 4 x : \frac{2 x}{2 x ^{2} + 2}

= \frac{2 x}{2 x ^{2} + 2}

\frac{\partial}{\partial y} ((1 + x y) e^{x y})

n = 1 \sum \infty \frac{9 ^{n}}{1 0 ^{n}}

\int sec^{3} (8 x) d x

\int x^{2} 2 x + 5 d x

t an g e n t y = \frac{3}{x}, (4, \frac{3}{2})