y^{''}+y^'+2y=0,y(0)=0,y^'(0)=0

Lösung

y^{^{''}} + y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Schritte zur Lösung

y^{''} (t) + y^{'} (t) + 2 y = 0

Solve linear ODE:

y = 0

y = 0

\int_{0}^{π} e^{- x} cos (2 x) d x

\frac{\partial}{\partial y} (ln (x + e^{- y}))

\int cos (a ln (\frac{x}{b})) d x

t an g e n t f (x) = \frac{1}{x - 2}

\frac{d}{d x} (3 1 + tan (x))