(dN)/(dt)+N=Nte^{t+3}

Lösung

\frac{d N}{d t} + N = Nt e^{t + 3}

N = e^{e^{3 + t} t - e^{3 + t} - t + c_{1}}

Schritte zur Lösung

\frac{d N}{d t} + N = Nt e^{t + 3}

Solve separable ODE:

N = e^{e^{3 + t} t - e^{3 + t} - t + c_{1}}

N = e^{e^{3 + t} t - e^{3 + t} - t + c_{1}}

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