(\partial)/(\partial x)(sin(7x-4y))

Lösung

\frac{\partial}{\partial x} (sin (7 x - 4 y))

cos (7 x - 4 y) \cdot 7

Schritte zur Lösung

\frac{\partial}{\partial x} (sin (7 x - 4 y))

Behandle

y

als Konstante

Wende die Kettenregel an:

cos (7 x - 4 y) \frac{\partial}{\partial x} (7 x - 4 y)

= cos (7 x - 4 y) \frac{\partial}{\partial x} (7 x - 4 y)

\frac{\partial}{\partial x} (7 x - 4 y) = 7

= cos (7 x - 4 y) \cdot 7

\frac{d ^{4}}{d x ^{4}} (16 e^{x^{2}})

\frac{d}{d x} (\frac{8 x + 3}{0.2 x ^{2} + 1})

y^{^{'}} = \frac{t}{y e ^{- y^{2}} + y e ^{- y^{2}} t ^{2}}

\frac{d}{d x} (- \frac{14}{x ^{4}})

d er i v a t i v e (\frac{( 3 x ^{2} )}{( 2 x + 4 )})^{3}