integral from 0 to 2pi of sqrt(2)

Lösung

\int_{0}^{2 π} 2

22 π

Dezimale

8.88576 \dots

Schritte zur Lösung

\int_{0}^{2 π} 2 d x

Integral einer Konstanten :

\int a d x = a x

= [2 x]_{0}^{2 π}

Berechne die Grenzen:

22 π

= 22 π

\frac{d}{d x} (x^{4} - 3 x^{2} + 4)

\frac{d}{d x} (\frac{6 x}{3 - cot ( x )})

\int_{0}^{\frac{π}{2}} 1 - 4 sin^{2} (x) d x

d er i v a t i v e 2 x^{- \frac{3}{4}}

d er i v a t i v e \frac{4}{cos ( x )} + \frac{1}{tan ( x )}