49y^{''}+28y^'+4y=0

Lösung

49 y^{^{''}} + 28 y^{^{'}} + 4 y = 0

y = c_{1} e^{- \frac{2 t}{7}} + c_{2} e^{- \frac{2 t}{7}} t

Schritte zur Lösung

49 y^{''} (t) + 28 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{2 t}{7}} + c_{2} e^{- \frac{2 t}{7}} t

y = c_{1} e^{- \frac{2 t}{7}} + c_{2} e^{- \frac{2 t}{7}} t

16 y^{^{''}} - 40 y^{^{'}} + 25 y = 0, y (0) = 3, y^{^{'}} (0) = - 94

x \to 0 lim (x \cdot sin (\frac{π}{x}))

m = \frac{9}{5 + h} - \frac{9}{5}

n = 1 \sum \infty e^{- n} + 1

\frac{d}{d x} (1 + \frac{1}{4 x})