derivative 3x^{1/4}(x^3-5)

解

導関数

3 x^{\frac{1}{4}} (x^{3} - 5)

\frac{3 ( 13 x ^{3} - 5 )}{4 x ^{\frac{3}{4}}}

解答ステップ

\frac{d}{d x} (3 x^{\frac{1}{4}} (x^{3} - 5))

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{\frac{1}{4}} (x^{3} - 5))

積の法則を適用:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{\frac{1}{4}}, g = x^{3} - 5

= 3 (\frac{d}{d x} (x^{\frac{1}{4}}) (x^{3} - 5) + \frac{d}{d x} (x^{3} - 5) x^{\frac{1}{4}})

\frac{d}{d x} (x^{\frac{1}{4}}) = \frac{1}{4 x ^{\frac{3}{4}}}

\frac{d}{d x} (x^{3} - 5) = 3 x^{2}

= 3 (\frac{1}{4 x ^{\frac{3}{4}}} (x^{3} - 5) + 3 x^{2} x^{\frac{1}{4}})

簡素化

3 (\frac{1}{4 x ^{\frac{3}{4}}} (x^{3} - 5) + 3 x^{2} x^{\frac{1}{4}}) : \frac{3 ( 13 x ^{3} - 5 )}{4 x ^{\frac{3}{4}}}

= \frac{3 ( 13 x ^{3} - 5 )}{4 x ^{\frac{3}{4}}}