y^'-8/x y=(y^3)/(x^{11)}

解答

y^{^{'}} - \frac{8}{x} y = \frac{y ^{3}}{x ^{11}}

y = \frac{3 x ^{8}}{- x ^{6} + c _{1}}, y = - \frac{3 x ^{8}}{- x ^{6} + c _{1}}

求解步骤

y^{'} (x) - \frac{8}{x} y = \frac{y ^{3}}{x ^{11}}

求解贝努力方程:

y = \frac{3 x ^{8}}{- x ^{6} + c _{1}}, y = - \frac{3 x ^{8}}{- x ^{6} + c _{1}}

y = \frac{3 x ^{8}}{- x ^{6} + c _{1}}, y = - \frac{3 x ^{8}}{- x ^{6} + c _{1}}

x \to 3 - lim (∣ x - 3 ∣)

\frac{d y}{d t} = 3 y (y - 2)

x y^{^{'}} + y = 2 x^{2}

\frac{d}{d x} (- 2 x + 9)

t an g e n t 3 x^{2} + 2 x, at x = - 1