integral of 4x^2+9

Lösung

\int 4 x^{2} + 9 d x

\frac{4 x ^{3}}{3} + 9 x + C

Schritte zur Lösung

\int 4 x^{2} + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{2} d x + \int 9 d x

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

\int 9 d x = 9 x

= \frac{4 x ^{3}}{3} + 9 x

Füge eine Konstante zur Lösung hinzu

= \frac{4 x ^{3}}{3} + 9 x + C

\frac{\partial}{\partial x} (x^{3} + x^{2} y)

\int \frac{cos ( 3 x )}{1 + sin ^{2} ( 3 x )} d x

x \to 0 lim (tan (2 x))

\frac{d}{d x} (3 x + 9)

s l o p e x - x^{3}