What is the derivative of 4^r ?

The derivative of 4^r is ln(2)*2^{2r+1}

What is the first derivative of 4^r ?

The first derivative of 4^r is ln(2)*2^{2r+1}

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derivative of

4^{r}

ln (2) \cdot 2^{2 r + 1}

Solution steps

\frac{d}{d r} (4^{r})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4^{r} ln (4)

Simplify

4^{r} ln (4) : ln (2) \cdot 2^{2 r + 1}

= ln (2) \cdot 2^{2 r + 1}

What is the derivative of 4^r ?
The derivative of 4^r is ln(2)*2^{2r+1}
What is the first derivative of 4^r ?
The first derivative of 4^r is ln(2)*2^{2r+1}