解答
∫1024sin4(x)cos4(x)dx
解答
1024(−41sin3(x)cos(x)+83(x−21sin(2x))−89(−61sin5(x)cos(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))−81sin7(x)cos(x))+C
求解步骤
∫1024sin4(x)cos4(x)dx
提出常数: ∫a⋅f(x)dx=a⋅∫f(x)dx=1024⋅∫sin4(x)cos4(x)dx
使用三角恒等式改写
=1024⋅∫sin4(x)(1−sin2(x))2dx
乘开 sin4(x)(1−sin2(x))2:sin4(x)−2sin6(x)+sin8(x)
=1024⋅∫sin4(x)−2sin6(x)+sin8(x)dx
使用积分加法定则: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx=1024(∫sin4(x)dx−∫2sin6(x)dx+∫sin8(x)dx)
∫sin4(x)dx=−41sin3(x)cos(x)+83(x−21sin(2x))
∫2sin6(x)dx=2(−6cos(x)sin5(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))
∫sin8(x)dx=−8cos(x)sin7(x)+87(−6cos(x)sin5(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))
=1024(−41sin3(x)cos(x)+83(x−21sin(2x))−2(−6cos(x)sin5(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))−8cos(x)sin7(x)+87(−6cos(x)sin5(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x)))))
化简 1024(−41sin3(x)cos(x)+83(x−21sin(2x))−2(−6cos(x)sin5(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))−8cos(x)sin7(x)+87(−6cos(x)sin5(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))):1024(−41sin3(x)cos(x)+83(x−21sin(2x))−89(−61sin5(x)cos(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))−81sin7(x)cos(x))
=1024(−41sin3(x)cos(x)+83(x−21sin(2x))−89(−61sin5(x)cos(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))−81sin7(x)cos(x))
解答补常数=1024(−41sin3(x)cos(x)+83(x−21sin(2x))−89(−61sin5(x)cos(x)+65(−41sin3(x)cos(x)+83(x−21sin(2x))))−81sin7(x)cos(x))+C