What is the derivative of g(x)=3x^4-140x^3 ?

The derivative of g(x)=3x^4-140x^3 is 12x^3-420x^2

What is the first derivative of g(x)=3x^4-140x^3 ?

The first derivative of g(x)=3x^4-140x^3 is 12x^3-420x^2

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derivative of

g (x) = 3 x^{4} - 140 x^{3}

12 x^{3} - 420 x^{2}

Solution steps

\frac{d}{d x} (3 x^{4} - 140 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (140 x^{3})

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (140 x^{3}) = 420 x^{2}

= 12 x^{3} - 420 x^{2}

What is the derivative of g(x)=3x^4-140x^3 ?
The derivative of g(x)=3x^4-140x^3 is 12x^3-420x^2
What is the first derivative of g(x)=3x^4-140x^3 ?
The first derivative of g(x)=3x^4-140x^3 is 12x^3-420x^2