y^'sin(x)+ycos(x)=0,y(pi/4)=1

Lösung

y^{^{'}} sin (x) + y cos (x) = 0, y (\frac{π}{4}) = 1

y = \frac{1}{2 sin ( x )}

Schritte zur Lösung

y^{'} (x) sin (x) + y cos (x) = 0

Solve separable ODE:

y = \frac{1}{2 sin ( x )}

y = \frac{1}{2 sin ( x )}

x \to 0 + lim ((\frac{1}{x})^{l n (x)})

d er i v a t i v e cos (ln (x))

\int_{0}^{1} \frac{e ^{- 2 x}}{2} d x

x \to 0 lim (sinh (x) cot (x))

n = 0 \sum \infty n x^{n}