What is the derivative of (x^2/(3x-4)) ?

The derivative of (x^2/(3x-4)) is (3x^2-8x)/((3x-4)^2)

What is the first derivative of (x^2/(3x-4)) ?

The first derivative of (x^2/(3x-4)) is (3x^2-8x)/((3x-4)^2)

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\frac{d}{d x} (\frac{x ^{2}}{3 x - 4})

\frac{3 x ^{2} - 8 x}{( 3 x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{3 x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 3 x - 4 ) - \frac{d}{d x} ( 3 x - 4 ) x ^{2}}{( 3 x - 4 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x - 4) = 3

= \frac{2 x ( 3 x - 4 ) - 3 x ^{2}}{( 3 x - 4 ) ^{2}}

Expand

2 x (3 x - 4) - 3 x^{2} : 3 x^{2} - 8 x

= \frac{3 x ^{2} - 8 x}{( 3 x - 4 ) ^{2}}

What is the derivative of (x^2/(3x-4)) ?
The derivative of (x^2/(3x-4)) is (3x^2-8x)/((3x-4)^2)
What is the first derivative of (x^2/(3x-4)) ?
The first derivative of (x^2/(3x-4)) is (3x^2-8x)/((3x-4)^2)