de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

integral of (2x^3+10x^2-3x+4)

Lösung

\int (2 x^{3} + 10 x^{2} - 3 x + 4) d x

Lösung

\frac{x ^{4}}{2} + \frac{10 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x + C

Schritte zur Lösung

\int 2 x^{3} + 10 x^{2} - 3 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{3} d x + \int 10 x^{2} d x - \int 3 x d x + \int 4 d x

\int 2 x^{3} d x = \frac{x ^{4}}{2}

\int 10 x^{2} d x = \frac{10 x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 4 d x = 4 x

= \frac{x ^{4}}{2} + \frac{10 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{4}}{2} + \frac{10 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x + C

Graph

Beliebte Beispiele

y^{^{''}} - 6 y^{^{'}} = 4 t

integral of (x-1)(x+2)(x+4)

\int (x - 1) (x + 2) (x + 4) d x

(dy}{dx}=\frac{(y-sqrt(x^2+y^2)))/x

\frac{d y}{d x} = \frac{( y - x ^{2} + y ^{2} )}{x}

yy^'=(y^2-y)(2x+5)

y y^{^{'}} = (y^{2} - y) (2 x + 5)

y^{''}+4y^'+5y=10

y^{^{''}} + 4 y^{^{'}} + 5 y = 10