derivative of-20x^3+36x^2-12x-4

解答

\frac{d}{d x} (- 20 x^{3} + 36 x^{2} - 12 x - 4)

- 60 x^{2} + 72 x - 12

求解步骤

\frac{d}{d x} (- 20 x^{3} + 36 x^{2} - 12 x - 4)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (20 x^{3}) + \frac{d}{d x} (36 x^{2}) - \frac{d}{d x} (12 x) - \frac{d}{d x} (4)

\frac{d}{d x} (20 x^{3}) = 60 x^{2}

\frac{d}{d x} (36 x^{2}) = 72 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (4) = 0

= - 60 x^{2} + 72 x - 12 - 0

化简

= - 60 x^{2} + 72 x - 12

\frac{d ^{2}}{d x ^{2}} (9 z^{2} e^{z})

\int_{0}^{8} \frac{1}{64 + x ^{2}} d x

\frac{d}{d x} (3 x^{2} - 3 x + 4)

n = 0 \sum \infty (- 0.3)^{n}

a re a x^{3} - x^{2} - 4 x - 4, 2 x - 4