ty^'+2y=4t^2

Lösung

t y^{^{'}} + 2 y = 4 t^{2}

y = t^{2} + \frac{c _{1}}{t ^{2}}

Schritte zur Lösung

t y^{'} (t) + 2 y = 4 t^{2}

Solve linear ODE:

y = t^{2} + \frac{c _{1}}{t ^{2}}

y = t^{2} + \frac{c _{1}}{t ^{2}}

x \to - 2 lim (\frac{x}{x ^{2} - 4})

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