derivative y=ln(8x^2-7x+9)

Lösung

ableitung von

y = ln (8 x^{2} - 7 x + 9)

\frac{16 x - 7}{8 x ^{2} - 7 x + 9}

Schritte zur Lösung

\frac{d}{d x} (ln (8 x^{2} - 7 x + 9))

Wende die Kettenregel an:

\frac{1}{8 x ^{2} - 7 x + 9} \frac{d}{d x} (8 x^{2} - 7 x + 9)

= \frac{1}{8 x ^{2} - 7 x + 9} \frac{d}{d x} (8 x^{2} - 7 x + 9)

\frac{d}{d x} (8 x^{2} - 7 x + 9) = 16 x - 7

= \frac{1}{8 x ^{2} - 7 x + 9} (16 x - 7)

Vereinfache

\frac{1}{8 x ^{2} - 7 x + 9} (16 x - 7) : \frac{16 x - 7}{8 x ^{2} - 7 x + 9}

= \frac{16 x - 7}{8 x ^{2} - 7 x + 9}

d er i v a t i v e f (t) = e^{9 t s i n (2 t)}

d er i v a t i v e \frac{x ^{2}}{x + 8}

\int 3 sec^{- 2} (x t a) n^{3} x d x

x \to 9 lim (2 x^{2} - 3)

\frac{\partial}{\partial x} (sin (x^{3}) + 3 x y)