((1+x^2)dy)/(dx)-(1+y^2)=0

Lösung

\frac{( 1 + x ^{2} ) d y}{d x} - (1 + y^{2}) = 0

y = tan (arctan (x) + c_{1})

Schritte zur Lösung

\frac{( 1 + x ^{2} ) d y}{d x} - (1 + y^{2}) = 0

Solve separable ODE:

y = tan (arctan (x) + c_{1})

y = tan (arctan (x) + c_{1})

\int_{0}^{N} e^{- s t} e^{- 5 t} d t

\frac{y d y + x d x}{2 1 + x y} = 0

\frac{d ^{2}}{d x ^{2}} ((x^{2} + 5)^{6})

\frac{\partial}{\partial x} (4 y^{2} x^{3})

\int_{0}^{1} (x + 1) (x^{2} + 2 x)^{5} d x