What is the solution for y^{''}-(2/x)y^'-(7/(x^2))y=0 ?

The solution for y^{''}-(2/x)y^'-(7/(x^2))y=0 is y=c_{1}x^{(3+sqrt(37))/2}+c_{2}x^{(3-sqrt(37))/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}-(2/x)y^'-(7/(x^2))y=0

y^{^{''}} - (\frac{2}{x}) y^{^{'}} - (\frac{7}{x ^{2}}) y = 0

y = c_{1} x^{\frac{3 + 37}{2}} + c_{2} x^{\frac{3 - 37}{2}}

Solution steps

y^{''} (x) - (\frac{2}{x}) y^{'} (x) - (\frac{7}{x ^{2}}) y = 0

Solve linear ODE:

y = c_{1} x^{\frac{3 + 37}{2}} + c_{2} x^{\frac{3 - 37}{2}}

y = c_{1} x^{\frac{3 + 37}{2}} + c_{2} x^{\frac{3 - 37}{2}}

What is the solution for y^{''}-(2/x)y^'-(7/(x^2))y=0 ?
The solution for y^{''}-(2/x)y^'-(7/(x^2))y=0 is y=c_{1}x^{(3+sqrt(37))/2}+c_{2}x^{(3-sqrt(37))/2}