integral of 3sec(2)(x)+2x-8x

Lösung

\int 3 sec (2) (x) + 2 x - 8 x d x

\frac{3}{2} sec (2) x^{2} - 3 x^{2} + C

Schritte zur Lösung

\int 3 sec (2) x + 2 x - 8 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 sec (2) x d x + \int 2 x d x - \int 8 x d x

\int 3 sec (2) x d x = \frac{3}{2} sec (2) x^{2}

\int 2 x d x = x^{2}

\int 8 x d x = 4 x^{2}

= \frac{3}{2} sec (2) x^{2} + x^{2} - 4 x^{2}

Vereinfache

= \frac{3}{2} sec (2) x^{2} - 3 x^{2}

Füge eine Konstante zur Lösung hinzu

= \frac{3}{2} sec (2) x^{2} - 3 x^{2} + C

\frac{\partial}{\partial x} (ln (7 x^{2} + x y))

y^{^{''}} + 3 y^{^{'}} + 2 y = cos (e x)

\int \frac{9 x ^{2}}{2} - 5 cos (x) + 7 d x

in v erse l a pl a ce - \frac{1}{s ^{2}}

\frac{\partial}{\partial x} (y + \frac{1}{x + y})