derivative f(x)=x^2-2x+1

Lösung

ableitung von

f (x) = x^{2} - 2 x + 1

2 x - 2

Schritte zur Lösung

\frac{d}{d x} (x^{2} - 2 x + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 x - 2 + 0

Vereinfache

= 2 x - 2

d er i v a t i v e 6 t - \frac{2}{t}

\frac{d}{d x} (\frac{1}{3} x^{3} - \frac{1}{2} x^{2} - 6 x)

in v erse l a pl a ce \frac{3 s + 17}{s ^{2} + s + 1}

t^{2} y^{^{''}} + 19 t y^{^{'}} + 106 y = 0

x \to 0 lim (tan (\frac{1}{x}))