derivative of-3x^3+2x^2+5x-2

Lösung

\frac{d}{d x} (- 3 x^{3} + 2 x^{2} + 5 x - 2)

- 9 x^{2} + 4 x + 5

Schritte zur Lösung

\frac{d}{d x} (- 3 x^{3} + 2 x^{2} + 5 x - 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{3}) + \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (5 x) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (2) = 0

= - 9 x^{2} + 4 x + 5 - 0

Vereinfache

= - 9 x^{2} + 4 x + 5

x \to 0 lim ((x^{2}) sin (\frac{1}{x}))

\int \frac{x ^{2} + x + 1}{x ^{3} + 2 x ^{2}} d x

\frac{\partial}{\partial y} (x e^{x} cos (y))

f (x) = 2 sin (2 x) - ln (3 x + 1)

\int cos (x) - cos^{2} (x) d x