What is area 7e^x,7xe^{x^2},1,7e ?

The answer to area 7e^x,7xe^{x^2},1,7e is -7(e^{7e}-e)+(7(e^{49e^2}-e))/2

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area 7e^x,7xe^{x^2},1,7e

area

7 e^{x}, 7 x e^{x^{2}}, 1, 7 e

- 7 (e^{7 e} - e) + \frac{7 ( e ^{49 e^{2}} - e )}{2}

Decimal

6.11443 E 157

Solution steps

Apply the area formula:

\int_{1}^{7 e} 7 e^{x} - 7 x e^{x^{2}} d x

Solve

\int_{1}^{7 e} 7 e^{x} - 7 x e^{x^{2}} d x : - 7 (e^{7 e} - e) + \frac{7 ( e ^{49 e^{2}} - e )}{2}

The area is:

= - 7 (e^{7 e} - e) + \frac{7 ( e ^{49 e^{2}} - e )}{2}

What is area 7e^x,7xe^{x^2},1,7e ?
The answer to area 7e^x,7xe^{x^2},1,7e is -7(e^{7e}-e)+(7(e^{49e^2}-e))/2