y^'+5y=e^{-3t}

Lösung

y^{^{'}} + 5 y = e^{- 3 t}

y = \frac{1}{2 e ^{3 t}} + \frac{c _{1}}{e ^{5 t}}

Schritte zur Lösung

y^{'} (t) + 5 y = e^{- 3 t}

Solve linear ODE:

y = \frac{1}{2 e ^{3 t}} + \frac{c _{1}}{e ^{5 t}}

y = \frac{1}{2 e ^{3 t}} + \frac{c _{1}}{e ^{5 t}}

in v erse l a pl a ce \frac{s + 2}{( s - 1 ) ( s + 3 ) ^{2}}

\int \frac{x + 1}{x + 10} d x

a re a f (x) = x^{2}, (0, 3)

\int \frac{1}{e ^{x} e ^{2 x} - 9} d x

\int x^{15} d x