What is the solution for (dx)/(dt)-4x=cos(4t) ?

The solution for (dx)/(dt)-4x=cos(4t) is x=(sin(4t))/8-(cos(4t))/8+c_{1}e^{4t}

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(dx)/(dt)-4x=cos(4t)

\frac{d x}{d t} - 4 x = cos (4 t)

x = \frac{sin ( 4 t )}{8} - \frac{cos ( 4 t )}{8} + c_{1} e^{4 t}

Solution steps

\frac{d x}{d t} - 4 x = cos (4 t)

Solve linear ODE:

x = \frac{sin ( 4 t )}{8} - \frac{cos ( 4 t )}{8} + c_{1} e^{4 t}

x = \frac{sin ( 4 t )}{8} - \frac{cos ( 4 t )}{8} + c_{1} e^{4 t}

What is the solution for (dx)/(dt)-4x=cos(4t) ?
The solution for (dx)/(dt)-4x=cos(4t) is x=(sin(4t))/8-(cos(4t))/8+c_{1}e^{4t}