5t^2y^{''}+ty^'-12y=0

Lösung

5 t^{2} y^{^{''}} + t y^{^{'}} - 12 y = 0

y = c_{1} t^{2} + \frac{c _{2}}{t ^{\frac{6}{5}}}

Schritte zur Lösung

5 t^{2} y^{''} (t) + t y^{'} (t) - 12 y = 0

Solve linear ODE:

y = c_{1} t^{2} + \frac{c _{2}}{t ^{\frac{6}{5}}}

y = c_{1} t^{2} + \frac{c _{2}}{t ^{\frac{6}{5}}}

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in v erse l a pl a ce \frac{s - 1}{2 s ^{2} + s + 3}