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Beliebt Rechnen >

y^'=(2xy)/(x^2-y^2),y(1)=1

Lösung

y^{^{'}} = \frac{2 x y}{x ^{2} - y ^{2}}, y (1) = 1

Lösung

y = 1 + - x^{2} + 1, y = 1 - - x^{2} + 1

Schritte zur Lösung

y^{'} (x) = \frac{2 x y}{x ^{2} - y ^{2}}

Solve using substitution:

y = 1 + - x^{2} + 1, y = 1 - - x^{2} + 1

y = 1 + - x^{2} + 1, y = 1 - - x^{2} + 1

Graph

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