(2x-1)dx+(5y+8)dy=0

Lösung

(2 x - 1) d x + (5 y + 8) d y = 0

y = \frac{- 16 + 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 16 - 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}

Schritte zur Lösung

(2 x - 1) d x + (5 y + 8) d y = 0

Solve separable ODE:

y = \frac{- 16 + 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 16 - 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}

y = \frac{- 16 + 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 16 - 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}

\int_{0}^{\frac{1}{3}} \frac{3}{1 + 9 x ^{2}} d x

\int_{- 5}^{1} ∣ x + 3 ∣ d x

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} + y^{2})

y^{^{'}} + 9 x^{- 1} y = x^{7}, y (1) = 8

\int (5 x - 3)^{2} (2 x - 1) d x