integral of (9+u+u^2)

Lösung

\int (9 + u + u^{2}) d u

9 u + \frac{u ^{2}}{2} + \frac{u ^{3}}{3} + C

Schritte zur Lösung

\int 9 + u + u^{2} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 d u + \int u d u + \int u^{2} d u

\int 9 d u = 9 u

\int u d u = \frac{u ^{2}}{2}

\int u^{2} d u = \frac{u ^{3}}{3}

= 9 u + \frac{u ^{2}}{2} + \frac{u ^{3}}{3}

Füge eine Konstante zur Lösung hinzu

= 9 u + \frac{u ^{2}}{2} + \frac{u ^{3}}{3} + C

\int \frac{4}{x ^{2} ( x - 2 )} d x

\int (x^{4} + x + 9) d x

d er i v a t i v e ln (\frac{x ^{2} - 1}{x ^{2} + 1})

in v erse l a pl a ce \frac{s ^{2} + 1}{s ^{2} ( s + 2 )}

\frac{\partial}{\partial y} (e^{- x} sin (yz))