4y^{''}+4y^'-3y=cos(2x)

Lösung

4 y^{^{''}} + 4 y^{^{'}} - 3 y = cos (2 x)

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{- \frac{3 x}{2}} + \frac{8}{425} sin (2 x) - \frac{19}{425} cos (2 x)

Schritte zur Lösung

4 y^{''} (x) + 4 y^{'} (x) - 3 y = cos (2 x)

Solve linear ODE:

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{- \frac{3 x}{2}} + \frac{8}{425} sin (2 x) - \frac{19}{425} cos (2 x)

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{- \frac{3 x}{2}} + \frac{8}{425} sin (2 x) - \frac{19}{425} cos (2 x)

\int_{2}^{3} \frac{26}{3 - x} d x

d er i v a t i v e f (x) = \frac{e ^{x}}{8 x ^{2} + 3}

n = 1 \sum \infty \frac{4 ^{n}}{6 ^{n}}

\int (((x)^{2} - 5)^{5} 2 x) d x

x \to - 1 + lim (ln ∣ x + 1 ∣)