18y^{''}+3y^'-10y=0

Lösung

18 y^{^{''}} + 3 y^{^{'}} - 10 y = 0

y = c_{1} e^{\frac{2 t}{3}} + c_{2} e^{- \frac{5 t}{6}}

Schritte zur Lösung

18 y^{''} (t) + 3 y^{'} (t) - 10 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{2 t}{3}} + c_{2} e^{- \frac{5 t}{6}}

y = c_{1} e^{\frac{2 t}{3}} + c_{2} e^{- \frac{5 t}{6}}

d er i v a t i v e \frac{1}{2 x + 1}

\frac{\partial}{\partial x} (- \frac{1}{x ^{2} + y ^{2}})

\frac{d}{d x} (\frac{5 x ^{2}}{x ^{2} + 1})

\int (15 x^{13}) d x

\int 9 x^{2} - 4 x + 3 d x