What is the derivative of f(t)=6t^3-54t^2+70 ?

The derivative of f(t)=6t^3-54t^2+70 is 18t^2-108t

What is the first derivative of f(t)=6t^3-54t^2+70 ?

The first derivative of f(t)=6t^3-54t^2+70 is 18t^2-108t

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derivative of

f (t) = 6 t^{3} - 54 t^{2} + 70

18 t^{2} - 108 t

Solution steps

\frac{d}{d t} (6 t^{3} - 54 t^{2} + 70)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (6 t^{3}) - \frac{d}{d t} (54 t^{2}) + \frac{d}{d t} (70)

\frac{d}{d t} (6 t^{3}) = 18 t^{2}

\frac{d}{d t} (54 t^{2}) = 108 t

\frac{d}{d t} (70) = 0

= 18 t^{2} - 108 t + 0

Simplify

= 18 t^{2} - 108 t

What is the derivative of f(t)=6t^3-54t^2+70 ?
The derivative of f(t)=6t^3-54t^2+70 is 18t^2-108t
What is the first derivative of f(t)=6t^3-54t^2+70 ?
The first derivative of f(t)=6t^3-54t^2+70 is 18t^2-108t