(\partial)/(\partial y)(sqrt(x+2)-y)

解答

\frac{\partial}{\partial y} (x + 2 - y)

- 1

求解步骤

\frac{\partial}{\partial y} (x + 2 - y)

将

x

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x + 2) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (x + 2) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 1

化简

= - 1

\int_{0}^{5} \frac{1}{x ^{\frac{12}{13}}} d x

a re a x^{2} - 4, 0, - 4, 3

\frac{\partial}{\partial y} (cos (x - y))

x \to 4 - lim (3 (x) - 5)

\frac{d}{d x} (\frac{8 e ^{x} + 5 e ^{- x}}{8})