integral from 0 to 5 of |15-5t|

Lösung

\int_{0}^{5} ∣ 15 - 5 t ∣ d t

\frac{65}{2}

Dezimale

32.5

Schritte zur Lösung

\int_{0}^{5} ∣ 15 - 5 t ∣ d t

Entferne die Extremwerte

= \int_{0}^{3} 15 - 5 t d t + \int_{3}^{5} - 15 + 5 t d t

\int_{0}^{3} 15 - 5 t d t = \frac{45}{2}

\int_{3}^{5} - 15 + 5 t d t = 10

= \frac{45}{2} + 10

Vereinfache

\frac{45}{2} + 10 : \frac{65}{2}

= \frac{65}{2}

\frac{d}{d x} (f (x) x^{^{'}} (x))

\frac{\partial}{\partial x} (ln (8 x^{2} + 3 y^{2} + 3))

\int \frac{10 x ^{4} - 9 x ^{2}}{2 x ^{5} - 3 x ^{3} + 14} d x

\frac{\partial}{\partial x} (\frac{5 y}{x ^{3}})

y^{^{''}} - 9 y^{^{'}} + 18 y = 5 sin (4 t), y (0) = 5, y^{^{'}} (0) = 2