(dy)/(dx)=kx

Lösung

\frac{d y}{d x} = k x

y = \frac{k x ^{2}}{2} + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = k x

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = k x

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int k x d x

\int k x d x = \frac{k x ^{2}}{2} + c_{1}

y = \frac{k x ^{2}}{2} + c_{1}

\int \frac{18 x ^{3} - 36 x ^{2} + 4}{x ^{2} - 2 x} d x

ma c l a u r in e^{8 x}

s l o p e (- 2, - 2), (- 1, 2)

\frac{\partial}{\partial x} (e^{x^{2} - y^{2} + 4 y})

\int_{1}^{4} (x^{2} - 2) d x