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受欢迎的微积分 >

sum from n=1 to infinity of n*e^{-n^2}

解答

n = 1 \sum \infty n \cdot e^{- n^{2}}

解答

收敛

求解步骤

n = 1 \sum \infty n e^{- n^{2}}

使用级数比值审敛法:

收敛

= 收敛

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