integral of 2x(x^2+2)^2

Lösung

\int 2 x (x^{2} + 2)^{2} d x

2 (\frac{x ^{6}}{6} + x^{4} + 2 x^{2}) + C

Schritte zur Lösung

\int 2 x (x^{2} + 2)^{2} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x (x^{2} + 2)^{2} d x

Multipliziere aus

x (x^{2} + 2)^{2} : x^{5} + 4 x^{3} + 4 x

= 2 \cdot \int x^{5} + 4 x^{3} + 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int x^{5} d x + \int 4 x^{3} d x + \int 4 x d x)

\int x^{5} d x = \frac{x ^{6}}{6}

\int 4 x^{3} d x = x^{4}

\int 4 x d x = 2 x^{2}

= 2 (\frac{x ^{6}}{6} + x^{4} + 2 x^{2})

Füge eine Konstante zur Lösung hinzu

= 2 (\frac{x ^{6}}{6} + x^{4} + 2 x^{2}) + C

\int 3 cos^{2} (x) d x

f (x) = x sin (x) + cos (x)

\frac{\partial}{\partial x} (sin (3 x + yz))

\int_{3}^{\infty} \frac{8}{x ^{2} - x} d x

in v erse l a pl a ce F (s) = \frac{6}{s ^{2} + 4}