(\partial)/(\partial x)(arcsin(2x-5))

Lösung

\frac{\partial}{\partial x} (arcsin (2 x - 5))

\frac{1}{- x ^{2} + 5 x - 6}

Schritte zur Lösung

\frac{\partial}{\partial x} (arcsin (2 x - 5))

Wende die Kettenregel an:

\frac{1}{1 - ( 2 x - 5 ) ^{2}} \frac{\partial}{\partial x} (2 x - 5)

= \frac{1}{1 - ( 2 x - 5 ) ^{2}} \frac{\partial}{\partial x} (2 x - 5)

\frac{\partial}{\partial x} (2 x - 5) = 2

= \frac{1}{1 - ( 2 x - 5 ) ^{2}} \cdot 2

Vereinfache

\frac{1}{1 - ( 2 x - 5 ) ^{2}} \cdot 2 : \frac{1}{- x ^{2} + 5 x - 6}

= \frac{1}{- x ^{2} + 5 x - 6}

a re a x = y^{2}, x = 36

x \to 0 lim (cos^{2} (x) - 1)

\int \frac{x ^{2} + 3 x + 2}{x ( x ^{2} + 2 x + 2 )} d x

y (1 + e^{x}) d y + (y^{4} + 1) d x = 0

n = 1 \sum \infty (sin (7))^{n}