integral from 0 to 6 of 12x-3x^2

解答

\int_{0}^{6} 12 x - 3 x^{2} d x

0

求解步骤

\int_{0}^{6} 12 x - 3 x^{2} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} 12 x d x - \int_{0}^{6} 3 x^{2} d x

\int_{0}^{6} 12 x d x = 216

\int_{0}^{6} 3 x^{2} d x = 216

= 216 - 216

化简

= 0

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