derivative of (4x^x)

解

\frac{d}{d x} ((4 x)^{x})

(ln (4 x) + 1) (4 x)^{x}

解答ステップ

\frac{d}{d x} ((4 x)^{x})

指数の規則を適用する:

a^{b} = e^{b l n (a)}

(4 x)^{x} = e^{x l n (4 x)}

= \frac{d}{d x} (e^{x l n (4 x)})

連鎖法則を適用:

e^{x l n (4 x)} \frac{d}{d x} (x ln (4 x))

= e^{x l n (4 x)} \frac{d}{d x} (x ln (4 x))

\frac{d}{d x} (x ln (4 x)) = ln (4 x) + 1

= e^{x l n (4 x)} (ln (4 x) + 1)

e^{x l n (4 x)} = (4 x)^{x}

= (ln (4 x) + 1) (4 x)^{x}